By Parviz Ghavami

This booklet, framed within the strategies of engineering research and layout, offers techniques in mechanics of fabrics for college students in two-year or four-year courses in engineering expertise, structure, and construction building; in addition to for college students in vocational colleges and technical institutes. utilizing the foundations and legislation of mechanics, physics, and the basics of engineering, Mechanics of fabrics: An creation for Engineering know-how can help aspiring and working towards engineers and engineering technicians from throughout disciplines—mechanical, civil, chemical, and electrical—apply ideas of engineering mechanics for research and layout of fabrics, buildings, and computing device elements. The publication is perfect for these looking a rigorous, algebra/trigonometry-based textual content at the mechanics of fabrics.

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3 Solution R ¼ þ8 þ 12 À 10 ¼ 10 N Therefore, three given forces may be replaced by a single force of 10 N in the positive direction (upward). Notice that the resultant of two collinear forces, for horizontal or vertical directions, can be found by the graphical method discussed earlier. 3 Find the force F that will produce equilibrium for the collinear forces shown (Fig. 4). 315 lb 185 lb 110 lb F? 424 lb Fig. , the resultant of the force system is equal to zero. 185 þ 110 þ 315 À 424 À F ¼ 0 Solving algebraically we get, F ¼ 186 lb 20 2 Force Systems on Structures Practice Problems 1.

1007/978-3-319-07572-3_3 51 52 3 Moment of a Force Point O is the O moment center ° r Mo m arm ent F 90 Line of action of force Fig. m. 2 Sign Convention of a Moment In the figure shown (Fig. 2), it is evident that the 100-lb force tends to rotate about point A in one direction, and about point B in the opposite direction. Some rule for the direction of rotation is then necessary. B 3′ 100# 5′ A Fig. 1 Find the moment of forces F1 ¼ 500 N and F2 ¼ 750 N with respect to point O. Assume r1 ¼ 2 m and r2 ¼ 3 m (Fig.

From B, draw a line BC in the direction of force F and of a length to represent 40 lb. Then the line AC is the resultant R in magnitude and direction. By measurement, R is found to be 50 lb. Angle α can be measured with a protractor. 11a shows the graphical solution by means of force triangle. 5 Determine the magnitude and direction of the resultant of two concurrent forces F1 ¼ 50 N and F2 ¼ 75 N acting on a body at an angle of 50 with each other (Fig. 12). Use the algebraic method only. 4 Resultant of Concurrent Forces 23 F2=75 N 50º F1=50 N Fig.